Math, asked by HarnoorSinghGill, 1 year ago

A man is 4times as old as his son. After 16 years he will be only twice as old as his son .Find their present ages

Answers

Answered by omimukeshpatel
224

Hope this will help you

Attachments:
Answered by mysticd
187

Answer:

At present :

At present :Son age = 8 years

At present :Son age = 8 yearsFather age = 32 years

Step-by-step explanation:

At present:

Age of son = x years

His Father age = 4x years

After 16 years:

Age of son = (x+16) years

Father age = (4x+16) years

According to the problem given,

 4x+16 = 2(x+16)

\implies 4x+16 = 2x+32

\implies 4x-2x=32-16

\implies 2x=16

\implies x = \frac{16}{2}

\implies x = 8

Therefore,

At present :

Son age = x = 8 years

Father age = 4x=4×8 = 32 years

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