Question

A man is 4times as old as his son. After 16 years he will be only twice as old as his son .Find their present ages

Answer 1

Hope this will help you

Answer 2

Answer:

At present :

At present :Son age = 8 years

At present :Son age = 8 yearsFather age = 32 years

Step-by-step explanation:

At present:

Age of son = x years

His Father age = 4x years

After 16 years:

Age of son = (x+16) years

Father age = (4x+16) years

According to the problem given,

$4x+16 = 2(x+16)$

$\implies 4x+16 = 2x+32$

$\implies 4x-2x=32-16$

$\implies 2x=16$

$\implies x = \frac{16}{2}$

$\implies x = 8$

Therefore,

At present :

Son age = x = 8 years

Father age = 4x=4×8 = 32 years

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