Question

A man is 4times as old as his son. After 16years he will be only twice as old as his son. Find their present ages.

Answer 1

Let present age of Son be x years

So, present age of Man be 4x years

After 16 years »

Son's age = (x + 16) years

Man's age = (4x + 16) years

According to Question,

(4x + 16) = 2(x + 16)

⇒ 4x + 16 = 2x + 32

⇒ 4x - 2x = 32 - 16

⇒ 2x = 16

⇒ x = 16 / 2

⇒ x = 8

Required present Ages »

Son's age = x = 8 years

Man's age = 4x = 4(8) = 32 years

Hence, the present age of the Man is 32 years and the present age of the Son is 8 years.

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