A man is 5 times as old as his son in 2 years time he will be four times as old as his son find their present ages
Answers
Answer :-
Present age of son is 6 years and present age of man is 30 years.
Solution :-
Let the present age of son be x
Man's age = 5 times son's age = 5(x) = 5x
In 2 years
Son's age = x + 2
Man's age = 5x + 2
Given that
In two years Man's age = 4 times of son's age in 2 years
⇒ 5x + 2 = 4(x + 2)
⇒ 5x + 2 = 4x + 8
Transpose 2 to RHS
⇒ 5x = 4x + 8 - 2
⇒ 5x = 4x + 6
Transpose 4x to LHS
⇒ 5x - 4x = 6
⇒ x = 6
Present age of son = x = 6 years
Present age of man = 5x = 5(6) = 30 years
Therefore the present age of son is 6 years and present age of man is 30 years.
Verification :-
Let us check
5x + 2 = 4(x + 2)
Substitute their present ages
⇒ 30 + 2 = 4(6 + 2)
⇒ 32 = 4(8)
⇒ 32 = 32
The Ages of Father and Son is 30 and 6 respectively.
Given :
A man is 5 times as old as his son
After 2 years - Man will be 4 times his son
To Find :
Their present Ages
Solution :
Consider the present age of the son as x
Father's age will be 5x as he is 5 times his son's age.
Ages after 2 years :
Father's age =
5x + 2
Son's age =
x + 2
As it is mentioned in the Question, in 2 years ; the Father's age is 4 times his son's age.
★
Son's age is 6 years.
★ Value of 5x
Father is 30 years old.
The Ages of Father and Son is 30 and 6 respectively.
As we know their present ages, We can add 2 years in their Ages to check if the condition mentioned in the Question matches.
Condition :
- Father is 4 times his son after 2 years
4 times 8 is 32.
The Ages of Father and Son is 30 and 6 respectively.