Question

a man is 5 times as old as his son . in two years of time he will be 4 times as old as his son find their present ages​

Answer 1

Explanation:

let,

son's age be = x

so, his father's age be = 5x

after 2 years

father's age = 5x + 2

son's age = x + 2

according to the question

4(x + 2) = 5x + 2

4x + 8 = 5x + 2

4x - 5x = 2 - 8

- x = - 6

so, x = 6

so, the present age of son is 6 and the present age of his father is 30.

Answer 2

Answer:

Let the age of the son of this man is be x years.

Therefore according to the question, the age of the man will be 5x. (as his age is five times his son's age).

After two years the age of the son will be x+2 years.

And hence, age of the man will be 4(x+2) years.

Now, we know that age of the father will be 5x+2 after two years.

Therefore:

4(x+2)=5x+2

4x+8= 5x+2

-x= -6

x=6

Present age of the son is 6 years and, present age of the father is 6×5 =30 years.