Question

A man is 5 times as old as his son, In two years time he will be four times as his son. Find their present ages​

Answer 1

Answer:

30 year and 6 year

Step-by-step explanation:

Let the present age of his son be x, so his present age must be 5x.

In two years,

Age of son = x + 2

Age of man = 5x + 2

 According to the question: he will be four times as his son.

⇒ 5x + 2 = 4 times of (x + 2)

⇒ 5x + 2 = 4(x + 2)

⇒ 5x + 2 = 4x + 8

⇒ 5x - 4x = 8 - 2

⇒ x = 6

 Present age of son is 6

and that of man is 5x = 5(6) = 30

Answer 2

Required answer:-

Question:

• A man is 5 times as old as his son, In two years time he will be four times as his son. Find their present ages.

Solution:

Given,

• Man is 5 times old as his son

• After two years his age will be four times his son.

To find:

• Present ages of man and his son

Let,

• Present age of man = x

( So, his son's age would be 5x )

Step by step explaination:

In two years

Age of son will be x+2

Age of man will be 5x+2

As, in two years age of man will be four times of his son age.

So,

5x + 2 = 4(x +2)

5x + 2 = 4x + 8

5x - 4x = 8 - 2

x = 6

As, x is 6

So present age of son = 6 years

present age of man = 5x = 5×6 = 30 years