A man is 56 years old and his son is 24 years old. In how many years,the father will be twice as old as his son at that time?
Answers
Answered by
176
Given, age of man =56 yrs.
age of his son =24 yrs.
Let, n be the years at which man's age will be twice of his son's age.
therefore,
56+n = 2(24+n)
56+n = 48+2n
56-48 = 2n-n
" 8 = n "
so, after 8years man's age will be twice of his son's age.
age of his son =24 yrs.
Let, n be the years at which man's age will be twice of his son's age.
therefore,
56+n = 2(24+n)
56+n = 48+2n
56-48 = 2n-n
" 8 = n "
so, after 8years man's age will be twice of his son's age.
Answered by
80
Age of man = 56 yrs
Age of son =24 yrs
Let x be the age at which father will be twice as old as his son.
A/Q
56 +x = 2(x+24)
56+x = 2x+48
56-48 = 2x -x
8 = x
Age of son =24 yrs
Let x be the age at which father will be twice as old as his son.
A/Q
56 +x = 2(x+24)
56+x = 2x+48
56-48 = 2x -x
8 = x
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