Question

a man is 6 times as old as his son, 20 years later, the man is twice the son's age. what is the man's age when his son was born

Answer 1

Answer:

25 years

Step-by-step explanation:

Sons age =x

Man's age =6x

According to the question,

(6x+20)=2(x+20)

6x+20=2x+40

Transposing,

6x-2x=40-20

4x=20

X=20/4

X=5

Man's age = 6x=30

Before 5 years, I. E son was born,

Fathers age =30-5=25 years

25 years

Answer 2

$\large{\underline{\red{\rm{AnswEr:25\: years}}}}$

$\huge\bold\red{\underline{Solution:}}$

$\bold\green{\underline{Let:}}$

The age of man be 6X

The age of his son be X

$\bold\green{\underline{Given:}}$

A man is 6 times as old as his son, 20 years later, the man is twice the son's age

$\bold\red{\underline{A.T.Q}}$

⟹6X+20=2(X+20)

⟹6X+20=2X+40

⟹6X-2X=40-20

⟹4X=20

⟹X=5

Now,

⟹The age of man=6X=6*5=30

⟹The age of his son=X=5

Hence,

The age of man when his son was born.

Subtract the age between a man and his son

⟹30-5

⟹25 years

$\bold\purple{\boxed{The\:age\:of\:the\:man=25\: years}}$