a man is 6 times old as his son. Twenty years later, the man will be twice as old as his son. Find the age of the man when his son was born.
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Answered by
0
Answer:
25
Step-by-step explanation:
Attachments:
Answered by
0
Answer:
25
Step-by-step explanation:
Present:
Son= x
Man= 6x (6 times old as his son)
After twenty years:
Son= x+20
Man= 6x+20
So,
6x+20 = 2(x+20)
6x+20 = 2x+40
6x-2x = 40-20
4x = 20
x = 20/4
x = 5
Therefore,
Son's present age= 5
Man's present age= 5 x 6 = 30
Age of Man when Son was born= 30-5
Answer- 25.
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