Math, asked by sylphansaari207, 1 day ago

a man is 6 times old as his son. Twenty years later, the man will be twice as old as his son. Find the age of the man when his son was born. ​

Answers

Answered by ah525407
0

Answer:

25

Step-by-step explanation:

Attachments:
Answered by zarrinaksd
0

Answer:

25

Step-by-step explanation:

Present:

Son= x

Man= 6x (6 times old as his son)

After twenty years:

Son= x+20

Man= 6x+20

So,

6x+20 = 2(x+20)

6x+20 = 2x+40

6x-2x = 40-20

4x = 20

x = 20/4

x = 5

Therefore,

Son's present age= 5

Man's present age= 5 x 6 = 30

Age of Man when Son was born= 30-5

Answer- 25.

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