Question

a man is 6 times old as his son. Twenty years later, the man will be twice as old as his son. Find the age of the man when his son was born. ​

Answer 1

Let the man be = x and his son be = y

Given:

x = 6y                         ..(1)

x + 20 = 2(y+20)        ..(2)

Substituting (1) in (2):

6y + 20 = 2(y + 20)

6y + 20 = 2y + 40

6y - 2y = 40 - 20

4y = 20

y = 5.                           ..(3)

Putting (3) in (1)

x = 6(5)

x = 30

Now, the age of the man when his son was born will be =

Current age of Father - Current Age of Son

30 - 5

= 25

The age of the man was 25 when his son was born

Answer 2

Answer:

Mark me as brainiest

Step-by-step explanation:

let the age of the son is x, then the age of the man is 6x . After 20 years the age of the man will be 6x + 20 and the age of the son will be x + 20 . Then 6x + 20 = 2 ( x + 20)

= 6x +20 = 2x + 40 - 20. 4x = 20

x = 5

Hence, the son is 5 years old and the father is 30 years old. Therefore father was 25 years old when his son was born.