Question

A man is 7 by 2 times as old as his son if the sum of the squares of their ages is 1325 find the ages of the father and the son

Answer 1

Answer:

Explanation:

  let the age of son be x and age of father be 7/2*x

so sum of the squares of their ages  = 1325

therefore x^2 + (7/2*x)^2                     = 1325

              x^2 + 49/4 * x^2                    = 1325

so after calculation we get  x = 10

therefore age of son = 10

so age of father  = 7/2*x = (7*10)/2 = 70/2 = 35