A man is 7 times and old as s son if the sum of the squares of their ages is 1325 , find the age of the father and son
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Let the age of son be x years so that the age of father is 7x .
The sum of squares of their ages is 1325
( x )^2 + ( 7x )^2 = 1325
x^2 + 49x^2 = 1325
50x^2 = 1325
x^2 = 1325/50
x^2 = 265/10
x^2 = 26.5
Seems that your question contains some mistakes please cjeak it once
Let the age of son be x years so that the age of father is 7x .
The sum of squares of their ages is 1325
( x )^2 + ( 7x )^2 = 1325
x^2 + 49x^2 = 1325
50x^2 = 1325
x^2 = 1325/50
x^2 = 265/10
x^2 = 26.5
Seems that your question contains some mistakes please cjeak it once
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