Question

A man is 7 times as old as his son. After 4 years, he will be 4 times as old as his son. Find the son's age.
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Answer 1

Answer:

Man age=28 years

Son's age=4years

Step-by-step explanation:

let the age of son be x.

Man's age =7x

After 4 years,

Son's age=x+4 years

Man's age=7x+4 years

Acc to Question

4(x+4)=7x+4

4x+16=7x+4

7x-4x=16-4

3x=12

x=12/3

x=4 years

7x=28 years

Hope it helps

Answer 2

Answer:

let the man's age be x and sons age be y

now according to question,

x=7y

also,

after 4 years mens age be= x+4

after 4 years son's age be=y+4

according to question

x+4=4(y+4)

x+4=4y+16

7y+4=4y+16(at, x=7y)

7y-4y=16-4

3y=12

y=12/3

y=4

x=7y

x=7×4

x=28

so ,man's age is 28 years and sons age is 4 years