Question

A man is 7 times as old as his son now. 4 years later,he will be 4 times as old as his son.Find their present ages.​

Answer 1

Answer:

attached below, hope it helps

Answer 2

Step-by-step explanation:

Let his son be x years old.

.

Son = x

Man = 7x

.

4 years later:

Son = x + 4

Man = 7x + 4

.

4 years later, Man is 4 times as old as his son:

7x + 4 = 4(x + 4)

.

Solve x:

7x + 4 = 4(x + 4)

7x + 4 = 4x + 16

7x - 4x = 16 - 4

3x = 12

x = 4

.

Find their present age:

Son = x = 4

Man = 7x = 7(4) = 28

.

Answer: The man is 28 years old and his son is 4 years old.