Question

A man is 7 times as old as his son now. 4 years later, he will be twice as old as eight times his son then. Find their present ages.

Answer 1

Let age of son is X and age of man be y
so acc to question
7x =y ....1
after 4 years
8(x+4 )=2(y+4)
8x+32=2y+8
8x-2y =-24
from eq 1
8x -14x = - 24
-6x =-24
x = 4
from eq 1
7×4 =28
so age of man is 28 years and his son is 4 years

Answer 2

Answer:

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