Question

A man is 7 times as old as his son now . four years later ,he will be 4 times as old as man.find their present age​

Answer 1

Answer:

Let the man be 7*x=7x

And, son be x

x*4=7x+4

Let the son age be 4 before

So,man=7*4=28

Present age of son=4+4

=8 years

present age of man=28+4

=32 years

=32/8=4

Man of 4 times old than son.

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Answer 2

Answer:

28

Step-by-step explanation:

If his son's age is 4 his father's age will be 28 after 4 years his age will be 8 and fathers will be 32 thus 8x4=32 and 4x7=28