Question

A man is 7 times as old as his son now. four years later, he will be 4 times as old as his son. find their present age.

Answer 1

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Answer 2

Let his son be x years old.

.

Son = x

Man = 7x

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4 years later:

Son = x + 4

Man = 7x + 4

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4 years later, Man is 4 times as old as his son:

7x + 4 = 4(x + 4)

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Solve x:

7x + 4 = 4(x + 4)

7x + 4 = 4x + 16

7x - 4x = 16 - 4

3x = 12

x = 4

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Find their present age:

Son = x = 4

Man = 7x = 7(4) = 28

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Answer: The man is 28 years old and his son is 4 years old.