A man is 7 times as old as his son. Two years ago, the man was 13 times as old as his son. find their present age
Answers
Answered by
7
Answer:
Refer the attached picture.
Attachments:
Answered by
1
Answer:
The father's age is 28 years and the son's age is 4 years.
Step-by-step explanation:
Let the age of father be f and the age of son be s.
According to the question,
f = 7 * s ...(i)
2 years ago, father's age = f - 2 and son's age = s - 2
f - 2 = 13( s - 2)
f - 2 = 13s - 26
13s - f = -2 + 26
13s - f = 24 ...(ii)
Use f = 7s in (ii)
13s - 7s = 24
6s = 24
s = 24/6
s = 4 years
use s = 4 in (i),
f = 7 * 4
f = 28 years.
∴The father's age is 28 years and the son's age is 4 years.
Similar questions