a man is 7 times old as his son now,4 yeaes later , he will be 4 times as old as his son. Find their present ages
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let father age be x
let sons age be y
atq
x=7y------(1)
x+4=4(y+4)
x+4=4y+16
x-4y=12-------(2)
from (1) and (2)
7y-4y=12
3y=12
y=4
x=4×7
x=28
father age 28 years
son age 4 years
let sons age be y
atq
x=7y------(1)
x+4=4(y+4)
x+4=4y+16
x-4y=12-------(2)
from (1) and (2)
7y-4y=12
3y=12
y=4
x=4×7
x=28
father age 28 years
son age 4 years
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