Question

a man is 7 times old as his son now,four years later,his age is 4 times the sons age . find his present age

Answer 1

Answer:

Step-by-step explanation:

Let man's age be m and son's age be s

Given m=7s ---- (1)

4 years later

Man's age = m+4

Son's age= s+4

m+4=4(s+4)

7s+4=4s+16

3s=12

s=4 years

Man's present age = 7s = 7(4) = 28 years