Question

a man is 9m behind a train at rest. the train starts with an acceleration of 2m/sec square and simultaneously the man starts running he is able ti bored the train somehow after 3 sec find the acceleration of man​

Answer 1

Explanation:

$for \: man \: \\ \\ u = 0 \\ d = 9m \\ \\ s = ut \: + 1 \div 2 at{}^{2} \\ 9 = 0 + 4.5a \\ \\ a = 9 \div 4.5 = 2m \: pr \: sec$