A man is apply a force 'F' on A 'M sq' area given by P=F/A. Find the pressure if force is increases to double but area is reduced to half
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Initial pressure is P= F/A
Final pressure is
P'= 2F / A/2
P'= 4F /A
Dividing by final pressure to initial pressure
P'/P = 4F /A × A/F
P'/P= 4
P'= 4F
Then the final pressure is 4 times of initial pressure.
Final pressure is
P'= 2F / A/2
P'= 4F /A
Dividing by final pressure to initial pressure
P'/P = 4F /A × A/F
P'/P= 4
P'= 4F
Then the final pressure is 4 times of initial pressure.
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