Question

A man is appointed on a salary of Rs. 3100 per month. He gets an increment (a grade) of Rs.80 every year. What is his monthly salary in the 10th year.

Answer 1

Answer:

Rs. 3820

Step-by-step explanation:

This is solved by AP

Initial salary = 3100

Increment each year = 80

To Find:- Salary in the 10th year

In the first year, he is appointed with Rs. 3100, and henceforth his salary has increased nine times and resulted in the salary of the 10th year.

So, in terms of AP,

a = 3100, d = 80, n = 10

So, Salary after 10 years = T10 = a + (n-1)d = 3100 + 9*80 = 3100 + 720

                                                                                             = Rs.3820