Math, asked by johnsonpjohn20981, 9 months ago

A man is asked to say 3 digit number .
(a) What is the probabity of the first and last digit be equal?
( b) What I athe probability thay the last 2 digit no be zero?
(c) What is the probablity that the last digit is greater than the first digit ?​

Answers

Answered by akhilesh1415ac
0

Step-by-step explanation:

The given statement says that 5 digit numbers are made from 7 digits.

The probability of selecting 5 digits from 7 is given by

7

P

5

The odd numbers are 4 in number and thus 2 of them can be selected by

4

P

2

and the remaining three from the even numbers as

3

P

3

Thus the probability is given by : (

4

P

2

x

3

P

3

)/(

7

P

5

) =

7

2

Answered by Shaima1234
3

Answer: a)1\10

b)1\100

Step-by-step explanation:

a) three digit no: 100,101,......,999

Total no: (999-100)+1=900

Total pairs :99

P(first and last digit to be equal) =90÷ 100=1\10

b)100,200,300,400,500,600,700,800,900

P(last two digit be 0) = 9÷900= 1\100

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