Question

A man is at distance of 6m from the bus the bus begins to move with a constant acceleration of 3 in order to catch the bus the minimum speed with which the man should run towards the bus is

Answer 1

v^2=u^2+2as
v^2=0+2(3)6
v^2=36
v=+6or-6

Answer 2

Answer:

6

Explanation:

v^2=u^2+2as

s=6

a=3

then,

v^2=(0)+36

v=6