A man is dealt 4 spade cards from an ordinary pack of 52 cards. if he is given three more cards, find the probability p that at least one of the additional cards is also a spade.
zainibrahim99:
P(A`/B)=P(A`∩B)/P(B)=39c3/48c3=9139/17296 then P(A/B)=1-9139/17296=8157/17296 .
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9/52 is the probability
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Given an ordinary deck of card and a man dealt four spade cards , find probability one of the additional three cards dealt is also a spade
Explanation:
- probability of choosing a particular card from a deck of cards is given by,
- since, four cards ( spades out of total ) are already dealt the total number cards are now and number of spades available are .
- hence, the probability of getting at least one spade on additional three cards is given as,
- now, the number of cards that are not spade are
- hence, the probability that at least one of the additional card is a spade is .
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