Math, asked by anshikatiwari1438, 1 year ago

A man is dealt 4 spade cards from an ordinary pack of 52 cards. if he is given three more cards, find the probability p that at least one of the additional cards is also a spade.


zainibrahim99: P(A`/B)=P(A`∩B)/P(B)=39c3/48c3=9139/17296 then P(A/B)=1-9139/17296=8157/17296 .

Answers

Answered by Barik7686
17
9/52 is the probability
Answered by sarahssynergy
3

Given an ordinary deck of card and a man dealt four spade cards , find probability one of the additional three cards dealt is also a spade

Explanation:  

  1. probability of choosing a particular card from a deck of cards is given by,             P(p)=\frac{no.\ of\ desired\ cards}{total\ no.\ of\ cards}  
  2. since, four cards ( 4 spades out of total 13) are already dealt the total number cards are now 48  and number of spades available are 9.
  3. hence, the probability of getting at least one spade on additional three cards is given as, p= 1-P(no\ card\ dealt\ is\ spade)    
  4. now, the number of cards that are not spade are 48-9=39                                    P(p)=1-\frac{C_3^{39}}{C_3^{48}} =1-\frac{9,139}{17,296} \\P(p)= \frac{8,157}{17,296} = 0.47  
  5. hence, the probability that at least one of the additional card is a spade is 0.47.

Similar questions