A man is five times as old as his son . 2 years ago he was 7 times as old as his son. find their present ages
Answers
Answered by
2
Answer:
Please follow me
Step-by-step explanation:
That is the required answer
Attachments:

Answered by
0
Answer:
Son = 6
Man = 30
Step-by-step explanation:
Current Ages :-
Son = x
man= 5x
Age 2 years ago :-
son= x-2
father = 5x-2 or 7(x-2)
So :-
5x-2 = 7(x-2)
5x-2 = 7x- 14
5x-7x= -14+2
-2x = -12
x = 12/2 (cut the minus (-) as it is on both sides)
x = 6
Son = 6
man= 5x6= 30
Similar questions
Social Sciences,
5 months ago
Math,
5 months ago
English,
10 months ago
History,
10 months ago
Math,
1 year ago