Math, asked by 13111980, 8 months ago

A man is five times as old as his son . 2 years ago he was 7 times as old as his son. find their present ages​

Answers

Answered by MrPerfect14
2

Answer:

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Step-by-step explanation:

That is the required answer

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Answered by jyotirmay77
0

Answer:

Son = 6

Man = 30

Step-by-step explanation:

Current Ages :-

Son = x

man= 5x

Age 2 years ago :-

son= x-2

father = 5x-2 or 7(x-2)

So :-

5x-2 = 7(x-2)

5x-2 = 7x- 14

5x-7x= -14+2

-2x = -12

x = 12/2 (cut the minus (-) as it is on both sides)

x = 6

Son = 6

man= 5x6= 30

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