Question

A man Is five times as old as his son.In two years time,he will be four times as old as his son.Find their present ages.​

Answer 1

Step-by-step explanation:

let present age of father be x

present age of son be y

father is 5times older than son

x = 5y

2 years later father's age will be x + 2

2 years later son's age will be y + 2

father's age will be 4 times of the son's age

x + 2 = 4(y + 2)

x + 2 = 4y + 8

x - 4y = 8 - 2

x - 4y = 6

substitute x = 5y

5y - 4y = 6

y = 6

x = 5y

x = 5 × 6

x = 30

father's age = 30 years

son's age = 6 years

hope you get your answer