Question

A man is five times as old as his son. In two years time, he will be four times as old as his son. Find their present age

Answer 1

let the present age of son be x year
then father's age is 5x year
After 2 years
son's age =x+2 year
father's age= 5x+2 year

ATQ
4(x+2)=5x+2
4x+8=5x+2
5x-4x=8-2
x=6

son's age = 6 year
father's age = 5×6=30 year

Answer 2

Step-by-step explanation:

please refer to the attachment