Question

A man is five times as old as his son. Two years ago, he was seven times as old as his son. Find their present ages.​

Answer 1

let age of son=x.

age of his father=5x

age of father 2 years ago=7(x-2)=7x-14.

7x-14=5x-2

2x=12.

x=6.

therefore,age of his son=6.

age of his father=5*6=30.

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Answer 2

30 ...................