Question

a man is five times as old as his son. Two years ago,he was seven times as old as his son. Find their present age.

Answer 1

Hello dear!!

Here's your answer

Let the age of son be x

Age of man = 5 x = y


Ages two years ago

Man = y - 2

Son = x - 2

Given (y-2) = 7(x-2)

y - 2 = 7x -14

But y = 5x

5x - 2 = 7x -14

2x = 12

x = 6 
y = 6(5) = 30

So, man is 30 years old and his son is 6 years old

Answer 2

HEY FRIEND

HERE IS YOUR ANSWER

Let the son's age be x

Then the man's age =5x

TWO YEARS AGO
______________

son's age=x-2

man's age=5x-2

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ACCORDING TO QUESTION :

(5x-2)=7(x-2)

5x-2=7x-14

14-2=7x-5x

12=2x

x=12/2

x=6

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SON'S AGE=6

MAN'S AGE=5x=5×6=30

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HOPE THIS HELPS YOU ☺