Question

A man is five times as old as his son two years ago he was 7 times as old as his son find their present ages

Answer 1

let the present ages of this man and son yand x

5x = y........ 1.

man is five times old as his son

before 2 years

age of man (y-2)

age of boy. ( x-2)

7(y-2) = x-2

7y - 14 = x- 2

7y -12 = x.............. 2

by subtracting 1 from 2

2y-12 = 0

2y= 12

y= 6

by substituting this value in 1

5y= x

30 = x

age of son = 6 = x

age of father = 30 = y

Answer 2

Step-by-step explanation:

answer is son,s present age is 6 years and

father present age is 5x 5×6 is 30