A man is five times old as his son. After 14 years he will be only thrice as old as his son. Find their present ages.
Given -
A man is five times old as his son. After 14 years he will be only thrice as old as his son.
To find -
Their present ages.
Solution -
Let the common ratio be termed as x
Son's age = x
man's age = 5x
After 14 yrs -
Son's age = x + 14
Man's age = 5x + 14
So,
now, we will make a linear equation, and then we will equate the whole expression.
On substituting the values -
\longrightarrow⟶ 5x + 14 = 3(x + 14)
\longrightarrow⟶ 5x + 14 = 3x + 42
\longrightarrow⟶ 5x - 3x = 42 - 14
\longrightarrow⟶ 2x = 28
\longrightarrow⟶ x = \sf\cancel\dfrac{28}{2}
2
28
\longrightarrow⟶ x = 14
Now -
Son's age = 14yrs
Man's age = 5 × 14 = 70yrs
\therefore∴ The present ages of man and son is 14yrs and 70yrs
Answers
Answer:
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Step-by-step explanation:
Given-
The man is 5 times old as his son. After 14 years he will be only thrice as op as his son
Let the common ratio be termed as x
son's age = x
man's age = 5x
After 14 yrs -
Son's age = x + 14
Man's age = 5x + 14
So,
now, we will make a linear equation, and then we will equate the whole expression.
On substituting the values -
\longrightarrow⟶ 5x + 14 = 3(x + 14)
\longrightarrow⟶ 5x + 14 = 3x + 42
\longrightarrow⟶ 5x - 3x = 42 - 14
\longrightarrow⟶ 2x = 28
\longrightarrow⟶ x = \sf\cancel\dfrac{28}{2}
2
28
\longrightarrow⟶ x = 14
Now -
Son's age = 14yrs
Man's age = 5 × 14 = 70yrs
\therefore∴ The present ages of man and son is 14yrs and 70yrs