Question

a man is five years as older as his son in 2 years times , he will be 4 times a old as his son . find percentage age ​

Answer 1

Step-by-step explanation:

Let Five years ago the age of son be x years and age of father be 7x years

Present age of son =x+5

Present age of father =7x+5

5 years later their age will (x+10) and (7x+10)

∴7x+10=3(x+10)

7x−3x=20

4x=20

x=5

So, the present age of son=x+5=5+5=10years

and the present age of father=7x+5=35+5=40years

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Answer 2

Answer:

The present age of the man is 30 years and the present age of the son is 6 years

Step-by-step explanation:

Let the age of the son be x

Let the age of the old man be 5x

The age after 2 years of the man = 5x + 2

The age after 2 years of the son = x + 2

According to the problem,

5x +  2 = 4(x + 2)

5x + 2 = 4x + 8

x = 6

Present age of the man = 5X6 = 30 yrs

Present age of the son = 6 yrs

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