A man is four times as old as his son. 10 years later, the man will be three times as old as his son. What is the man’s current age?
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Answers
Answer:
ANSWER
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Let the Man's age be x years and his son's age be y years
It is given :
x = 4y -------------- (i)
After 20 years their ages will be
Man : x + 20
Son : y + 20
x + 20 = 2 ( y + 20 ) ----------------- (ii)
Substituting value of x in equation (ii) with 4y
=> 4y + 20 = 2y + 40
=> 4y - 2y = 40 - 20
=> 2y = 20
=> y = 10 years
Using in eq (i)
x = 4y
=> x = 40 years
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ANSWER :
Man's age = 40 yrs.
Son's age = 10 yrs.
Answer:
Let the man's age be x yrs and his son's age be y yrs .
According to the conditions ;
x = 4y ---(1)
x + 10 = 10y
x = 10y + 100 ----(2)
substituting eq (1) in eq (2)
4y = 10y + 100
-6y = 100
y = 100/ -6
but as we know yrs cannot be negative so ...
y = 1.6 ---(3)
substituting eq (3) in eq (1)
x = 4 × 1.6
x = 6.6
The man's age is 6.6 yrs and his sons age is 1.6 yrs .