Question

A man is four times as old as his son. After 10 yrs, he will be be twice as old as his son . Find there present ages

it's urgent pls answer it ​

Answer 1

Consider the present age of son =x years

So the present age of father =4x years

After 20 years

$\sf \: Age \: of \: son =(x+20)years$

$\sf \: Age \: of \: father =(4x+20)years$

Based on the condition

$\sf \: 4x+20=2(x+20) \:$

By further calculation

$\sf \: 4x+20=2x+40$

$\sf \red{2x=20}$

So we get

$\pink{ \bf \: x=10}$

So the present age of son =10 years

Present age of father =4×10=40 years.

Hence, This is Answer.