Question

A man is four times as old as his son After 16 years he will be only twice as old as his son find the their parent age​

Answer 1

Answer:

Let us the present age of son be X

And his father's age be (×+4)

After 16 years.

His son's age =2 (×)=16

or, 2x=16

x=16 /2=8 years.

His father's age =(x*4)

=(8×4)

=32 years

Father's age 32 yrs

Son's age 16 yrs.

Answer 2

Answer:-

Son age = 8 years

Parent age = 32 years

Solution :-

Let the age of his parent be x years and the son be y years.

Case :- 1

A man is 4 times old as his son.

$x = 4y -------eq. 1$

Case :- 2

After 16 years.

The age of man after 16 years will be = ( x + 16 )

Son age after 16 years will be =

Son age after 16 years will be = ( y + 16 )

The man age will be twice old as his son.

$( x + 16) = 2 ( y + 16 )$

→$x + 16 = 2y + 32$

→$x - 2y = 32 -16$

→$x -2y = 16 -----eq. 2$

Put the value of x in eq. 2

→$x = 4y$

→$x -2y = 16$

→$4y -2y = 16$

→$2y = 16$

→$y = \dfrac{16}{2}$

→$y = 8$

Now , put the value of y in eq. 1

→x = 4y

→x = 4 × 8

→x = 32

hence, the age of son will be 8 years and his parent will be 32 years.