Question

A man is four times as old as his son. After 16 years, he

will be only twice as old as his son. Find their present

ages ?​

Answer 1

Let the present age of father be x and the son be y.

Now, x = 4y ---------- (1)

After 16 years,

age of father will be x+ 16

age of son will be y +16

Therefore, x + 16 = 2( y + 16)

x + 16 = 2y + 32

x = 2y + 16

or 4y = 2y + 16 {Using equation (a)}

2y = 16

y = 8

Plugging back the value of y in equation (1), we get:

x = 4*8 = 32

Hence, the present age of father is 32 years and present age of son is 8 years.

Answer 2

Answer:

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