A man is four times as old as his son after 16 years he will be only twice as old as his son find their present age
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prithvirajrajan:
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Let his son's age be x
Then Father's age will be 4x
After 16 years
Son's age will be x+16
Father's age will be 4x+16
Given that after 16 years he will be twice as old as his son
therefore, Son's age will be 2(x+16)
There present ages:
4x+16=2x+32
4x-2x=32-16
2x=16
x=8
Therefore, Son's age (x)=8
Father's age (4x)=32
Then Father's age will be 4x
After 16 years
Son's age will be x+16
Father's age will be 4x+16
Given that after 16 years he will be twice as old as his son
therefore, Son's age will be 2(x+16)
There present ages:
4x+16=2x+32
4x-2x=32-16
2x=16
x=8
Therefore, Son's age (x)=8
Father's age (4x)=32
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