Question

A man is four times as old as his son. After 2 years, he will be twice as old as his son at that time​

Answer 1

Step-by-step explanation:

Let the son age is x

Man age = 4x

After 2 years

Son age = x+2

Man age = 4x+2

By the problem

4x+2=2(x+2)

4x+2=2x+4

4x-2x=4-2

2x=2

x=1

The son age is = 1

And the man age is 4

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Answer 2

Answer:

4 years

Step-by-step explanation:

Let the age of his son be x.

Then, the age of the man will be 4x.

After 2 years,

Age of son = (x+2) years

Age of father = (4x+2) years

Based on the condition,

4x+2=2(x+2)

By further calculation,

4x+2=2x+4

2x=2

So we get

x=1

So the present age of son =1 years

Present age of father =4×1 =4 years.

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