Question

A man is four times as old as his son. After 20 years , he will be twice as old as his son at that time . Find their present ages.

Answer 1

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Answer 2

ANSWER
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Let the Man's age be x years and his son's age be y years

It is given :

x = 4y -------------- (i)

After 20 years their ages will be
Man : x + 20
Son : y + 20

x + 20 = 2 ( y + 20 ) ----------------- (ii)


Substituting value of x in equation (ii) with 4y

=> 4y + 20 = 2y + 40

=> 4y - 2y = 40 - 20

=> 2y = 20

=> y = 10 years

Using in eq (i)

x = 4y

=> x = 40 years

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ANSWER :

Man's age = 40 yrs.
Son's age = 10 yrs.
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