Question

A man is four times as old as his son after 20 years he will be twice as old as his son at that time find their present ages

Answer 1

Let x be the age of his son now, then the age of the father is 4x.
In 20 years,
The son's age = x + 20
The father's age = 4x + 20
As in 20 years the father will be twice as old as his son, we can set up an equation:

4x + 20 = 2(x + 20)
Solving the equation for x, we have
4x + 20 = 2x + 40
2x = 20
x = 10
So the age of his son now is 10, and the age of the the father now is 40




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Answer 2

Let son age be x A man is four times as his son=4x After 20 years twice as son age=4x+20=2(x+20) =4x+20=2x+40 4x-2x=40-20. 2x=20 . x=10 son age=10 father age=4×10=40