Math, asked by sheetalch2008, 1 day ago

A man is four times as old as his son. After 20 years, he will be twice as old as his son at that time. Find their present ages. d the number.​

Answers

Answered by choudharypriyanka746
0

Answer:

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Answered by JOSHVIN07
1

Answer:

Answer is

Father = 40

son = 10

Step-by-step explanation:

Let x be the age of son

NOW

Man = 4x

Son = x

After 20 years

Man = 4x + 20

Son = x + 20

Equation

4x + 20 = 2(x + 20)

(multiplying with 2 because given as Man is twice as old as son)

4x + 20 = 2x + 40

(opening the brackets)

4x -2x = 40 - 20

2x = 20

There fore

x= 20/2 = 10

Man = 4x = 4 × 10 = 40

Son = x = 10

After 20 years

Man = 60

Son = 30

Man is twice as old as son after 20 years

I hope you understood

if so mark me as brainliest

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