A man is four times as old as his son. After 20 years, he will be twice as old as his son at that time. Find their present ages. d the number.
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Answer:
Answer is
Father = 40
son = 10
Step-by-step explanation:
Let x be the age of son
NOW
Man = 4x
Son = x
After 20 years
Man = 4x + 20
Son = x + 20
Equation
4x + 20 = 2(x + 20)
(multiplying with 2 because given as Man is twice as old as son)
4x + 20 = 2x + 40
(opening the brackets)
4x -2x = 40 - 20
2x = 20
There fore
x= 20/2 = 10
Man = 4x = 4 × 10 = 40
Son = x = 10
After 20 years
Man = 60
Son = 30
Man is twice as old as son after 20 years
I hope you understood
if so mark me as brainliest
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