Question

A man is four times as old as his son after twenty years he will be twice as old as his son at that time find their present age

Answer 1

son age be x
man age be 4x
after 20 years
son age = x + 20 years
man age = 4x + 20 years
a/q to question
4x +20 = 2 (x+20)
4x + 20 = 2x + 40
2x = 20
x = 10
son age = 10 years
man age = 10 *4 = 40 years
@trisha __:)

Answer 2

this is ur answer hope it helps