Question

A man is four times as old as his son. The difference between their ages is 36 years. Find the sum of their ages.

Answer 1

Answer: Difference between their age is 36 years. S=12, that is, age of son is 12 years. Age of the man = 4*S = 4*12 = 48. Sum of their ages = 48 + 12 = 60.

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Answer 2

Answer:

Given:

• A man is four times as old as his son.
• The difference between their ages is 36 years.

Find:

• Find the sum of their ages.

Calculations:

• According to the question, let x be the common variable, and let 4x be the father.

=> 4x - x = 36

=> 3x = 36

=> x = 12

Therefore, 12 years is the age of son.

Finding the sum of their ages:

=> 4x = 12 (4) = 48.

=> 4x = 12 + 48

=> 4x = 60

Therefore 60 years is the answer.