Question

A man is four times as old as his son. The difference between their ages is 36 years .Find sum of their ages.(Waec,May/June2001)

Answer 1

Answer:

60 yrs....

Step-by-step explanation:

Let the son's age be x

man's age - 4x

4x-x = 36

3x = 36

x = 12

there the sum of there ages is 4x+x 5x = 5*12= 60

Answer 2

Step-by-step explanation:

let the age of his son be x

age of the man is 4x and x+36

Therefore 4x = x +36

= 4x-x = 36

3x= 36

x= 36/3=12

so age of man = 48 and sum = 60