Question

A man is four times as old as his son.Twenty years later he will be just twice as old as his son.Find their present age.
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Answer 1

Answer:

son is 10, father is 40

Step-by-step explanation:

10 x 4 + 40  = first part of equation. 30 x 2 = 60, or 40 + 20

Answer 2

Step-by-step explanation:

Consider the present age of son =x years

So the present age of father =4x years

After 20 years

Age of son =(x+20)years

Age of father =(4x+20)years

Based on the condition

4x+20=2(x+20)

By further calculation

4x+20=2x+40

2x=20

So we get

x=10

So the present age of son =10 years

Present age of father =4×10=40 years.