Question

A man is instructed to carry a package form the baseccamp at B to summit A of a hill at a hight of 1200m the man weight 800N and package weight 200N.if g= 10m/s2 what is the potential energy of the package at A if it is assumed to be zero at B?

Answer 1

(A)The work done against the gravity will be stored in the form of potential energy

Work done = mgh

here weight will be equal to force i.e f = w = mg

which acts downwards hence we have work done =w×h

Here

w= mg = (800+200) N = 1000 N

Therefore,W = mgh = 1000 N x 1200 m = 1200000 = 1.2 x 106 joules

(B) potential energy of the package at A will be equal to the work done

but in this case the weight will be of package only

and hence at h = 1200 m

with weight w = 200 N

potential energy will be equal to 200 *1200 m

so P.E=240000 Nm = 2.4 × 105 j.

Hope it helps!!

Answer 2

Answer:

(A)The work done against the gravity will be stored in the form of potential energy

Work done = mgh

here weight will be equal to force i.e f = w = mg

which acts downwards hence we have work done =w×h

Here ,

w= mg = (800+200) N = 1000 N

Therefore, W = mgh = 1000 N x 1200 m = 1200000 = 1.2 x 106 joules

(B) potential energy of the package at A will be equal to the work done

but in this case the weight will be of package only

and hence at h = 1200 m

with weight w = 200 N

potential energy will be equal to 200 *1200 m

so P.E=240000 Nm = 2.4 × 105 J

This is your answer

Hope it helps!!

Explanation: