Question

A man is instructed to carry a package from a base camp at B to summit A of a hill at height of 1200 m. The man weighs 200 N. If g= 10m/s2 , i. How much work does the man do against the gravity? ii. What is the potential energy of the package at A if it is assumed to be zero at B?

Answer 1

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Answer 2

$\huge{\underline{\underline{\red{\sf{Correct \: Question :}}}}}$

A man is instructed to carry a package from the base camp at B to submit A of a hill at a height of 1200 metres. The man weighs 800 N and the package weighs 200 N. If g = 10 m/s2,

(i) How much work does man do against gravity ?

(ii) What is the potential energy of the package at A if it is assumed to be zero at B ?

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$\huge{\underline{\underline{\red{\sf{Answer :}}}}}$

$\large \tt Given \begin{cases} \sf{Men \: weight \: = \: 800 \: N} \\ \sf{Package \: Wight \: = \: 200 \: N} \\ \sf{Height \: of \: hill \: = \: 1200 \: m} \end{cases}$

Solution :

(i) Work Done

Total Wight = 800 N + 200 N

Total Weight = 1000 N

We have formula for Work Done

$\Large{\underline{\boxed{\sf{Work \: Done \: = \: Force \: \times \: displacement }}}}$

Where,

displacement = h = 1200 N

Force = mg = 1000

Put Values

⇒Work = 1200*1000

⇒Work = 1200000

∴ Work Done is 12*10^5 J

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(ii) Potential Energy of package.

We have formula for Potential Energy

$\Large{\underline{\boxed{\sf{P.E \: = \: mgh}}}}$

Here we will take only weigh of Package

Weight of Package = mg = 200 N

Put Values

⇒ P.E = 200 * 1200

⇒P.E = 240000

∴ Potential Energy is 2,40,000 J

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