Question

A man is instructed to carry a package from the base camp at b to submit a at a hill at a height of 1200 meters . the man weight 800 N and the package weight 200 N
(1) how much work does man do against gravity?
(2) what is the potential energy of package at A if it is assumed to be 0 at B​

Answer 1

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let m be mass of body

M be mass of object to be carried

then mg= 800N, m= 800÷9.8=81.63 Kg

& Mg=200N, M= 200÷g= 200÷9.8= 20.41 kg

workdone by person= (800N+200N)×1200m

= 12×10^5 Nm

Potential energy=(M+m)gh

= [81.63+20.41]×9.8×1200

=1199990.4 kgm2/s2

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