Question

A man is is 24 years older than his son.in two years, his age will be twice the age of his son.calculate the present age of his son is

Answer 1

let the age of man is x years
age is his son is y years.
$x = y + 24 \\ x - y = 24 \: \: \: \: eq1 \\ x + 2 = 2(y + 2) \\ x + 2 = 2y + 4 \\ x - 2y = 2 \: \: \: \: \: eq2 \\ subtract \: both \: eq \\ y = 22 \\ x - 22 = 24 \\ x = 24 + 22 \\ x = 46$
father's age 46 years
son age 22 years

Answer 2

Answer:

Let the sons present Age be x years.

Then, Mans present age will be (x + 24) years.

According to Question :

➳ x + 24 + 2 = 2(x + 2)

➳ x + 26 = 2x + 4

➳ 26 - 4 = 2x - x

➳ x = 22 years

Therefore,the present age of his son is 22 years